acceleration up the hill is due to gravity and the force of friction.
forcedownhill=mg*sinTheta+mg*mu*cosTheta
acceleration= forcedownhill/m
Now down the hill,
force down hill= mgSinTheta-mg*mu*cosTheta
A toboggan approaches a snowy hill moving at 11.1 m/s . The coefficients of static and kinetic friction between the snow and the toboggan are 0.410 and 0.280, respectively, and the hill slopes upward at 42.0 ∘ above the horizontal.
A)Find the acceleration of the toboggan as it is going up the hill.
B)Find the acceleration of the toboggan after it has reached its highest point and is sliding down the hill.
1 answer
1 answer