A titration of a NH3 and HCl. The NH3 has a molarity of 0.3M and a pH of 11.37, whereas the HCl has a molarity of 0.2M and a pH of 0.7. What is the equivalence point of these titration?

1 answer

To determine the equivalence point of the titration between ammonia (NH₃) and hydrochloric acid (HCl), we first need to understand what occurs at the equivalence point.

  1. Ammonia (NH₃) is a weak base and when titrated with hydrochloric acid (HCl), a strong acid, they react to form ammonium chloride (NH₄Cl): \[ \text{NH}_3(aq) + \text{HCl}(aq) \rightarrow \text{NH}_4^+(aq) + \text{Cl}^-(aq) \]

  2. At the equivalence point, all of the NH₃ will have reacted with an equivalent amount of HCl.

  3. To find the equivalence point, we determine the moles of each solution involved:

Let \( V_1 \) be the volume of NH₃ solution and \( V_2 \) be the volume of HCl solution used. The number of moles of each reactant can be expressed as:

  • Moles of NH₃ = \( 0.3 , \text{M} \times V_1 \)
  • Moles of HCl = \( 0.2 , \text{M} \times V_2 \)

At the equivalence point, the moles of NH₃ will equal the moles of HCl: \[ 0.3 , V_1 = 0.2 , V_2 \] \[ \frac{V_1}{V_2} = \frac{0.2}{0.3} = \frac{2}{3} \]

This shows that for every 2 mL of NH₃, we need 3 mL of HCl to reach the equivalence point.

  1. Now, we look at the pH at the equivalence point. At this point, only NH₄⁺ (the conjugate acid of NH₃) and Cl⁻ ions will be present in the solution. NH₄⁺ can donate a proton to water, acting as a weak acid: \[ \text{NH}_4^+ + \text{H}_2\text{O} \rightleftharpoons \text{NH}_3 + \text{H}_3\text{O}^+ \]

  2. To find the pH at the equivalence point, we must calculate the concentration of \( \text{NH}_4^+ \) after titration, then use \( K_a \) for the dissociation of NH₄⁺. The \( K_a \) can be calculated from the \( K_b \) of NH₃ which is approximately \( 1.8 \times 10^{-5} \): \[ K_a = \frac{K_w}{K_b} = \frac{1.0 \times 10^{-14}}{1.8 \times 10^{-5}} \approx 5.56 \times 10^{-10} \]

  3. The pH can be found from the concentration of NH₄⁺ and the equilibrium expression for \( K_a \): \[ K_a = \frac{[\text{NH}_3][\text{H}_3\text{O}^+]}{[\text{NH}_4^+]} \]

Assuming the concentration of \( \text{NH}_4^+ \) at the equivalence point is \( C \), then we can derive the pH. The pH is not straightforward to calculate because it requires solving for equilibrium concentrations, but typically for dilute solutions, you can estimate.

  1. Typically, the pH at the equivalence point of a weak base (NH₃) with a strong acid (HCl) will be below 7, likely in the range of 5-6 due to the formation of NH₄⁺.

In summary, at the equivalence point, the solution is composed of NH₄Cl. The general pH at the equivalence point of this reaction is likely between 5-6, but precise calculation would require detailed information on the volumes used, and potentially some further calculations to determine the concentrations and the resulting hydronium concentration.