1 bar = 100000 Pa
2.8 bar =2.8•10^5 Pa
T1= 273+10 =283 K
T2 =273+35 =308 K
p1/T1 =p2/T2
p2=p1•T1/T2 = 2.8•10^5•283/308 =257272.7 Pa
a tire contains air ata pressure of 2.8 bar at 10 degree celsius.if the tires volume is unchanged what will the air pressure in it be when the tire warms up to 35 degree celsius if the car is driven.
4 answers
257600
When you cross multiply the original formula you get: p1T2/T1.
Therefore you would get: (2.8 x 10^5)(308)/(283) = p2
Therefore you would get: (2.8 x 10^5)(308)/(283) = p2
3.0
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