To find the probability of selecting a pecan and then selecting another pecan, we first calculate the probability of selecting a pecan on the first draw.
The total number of nuts in the tin is 11 + 25 + 20 + 16 = 72.
The probability of selecting a pecan on the first draw is 25/72.
Now that one pecan has been selected, there are 24 pecans remaining out of the total of 71 nuts.
The probability of selecting another pecan on the second draw is 24/71.
Therefore, the probability of selecting a pecan and then selecting another pecan is:
(25/72) * (24/71) = 600/5112 = 25/212 ≈ 0.1179
So, the probability is 25/212 or approximately 0.1179.
A tin of nuts contains 11 cashews, 25 pecans, 20 peanuts, and 16 pistachios. Find the probability of reaching in and selecting a pecan and then selecting another pecan.
Assume the nuts are chosen without replacement. Express your answer as a fraction in lowest terms or a decimal rounded to the nearest millionth.
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