(a)

Tim charted his distance from home. Click Here for Help Video

Plot the point (10, 16).

Point
Segment
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Minutes

Distance from home (in miles)

0 24681012141618202468101214161820ABCDEFGHIJ
(b)
How many total minutes did Tim stop to rest?


How many times did Tim get closer to his home?


The speed from the 14th minute to the 18th minute is miles
per hour. (Remember that speed is never negative.)

1 answer

To answer the questions, I need to provide some context. Since I can't access the video you mentioned, I'll guide you through the analysis assuming a typical situation involving a distance-time graph.

(a) Plotting the point (10, 16):

  1. Locate the x-axis (Minutes) and the y-axis (Distance from home in miles).
  2. Find where \(x = 10\) minutes on the x-axis.
  3. Move up to \(y = 16\) miles and place a point there.

(b) Questions:

  1. Total minutes Tim stopped to rest:

    • To determine how long Tim stopped, look for flat sections in the distance-time graph where the distance remains constant for a period of time. Count the total minutes in these flat sections to get the total resting time.
  2. How many times Tim got closer to his home:

    • Review the graph for sections where the distance from home decreases. Each time the line goes downwards represents a time Tim got closer. Count how many such intervals exist.
  3. Speed from the 14th to the 18th minute:

    • To calculate speed, you'll need the distance at both the 14th and 18th minutes.
    • Speed is calculated using the formula: \[ \text{Speed} = \frac{\text{Distance traveled}}{\text{Time taken}}. \]
    • First, find the distance at 14 minutes and the distance at 18 minutes.
    • The distance traveled is the change in distance (distance at 18 minutes - distance at 14 minutes), and the time taken is 4 minutes.
    • To convert the speed to miles per hour (since there are 60 minutes in an hour), use: \[ \text{Speed in miles per hour} = \left(\frac{\text{Distance traveled}}{4 \text{ minutes}}\right) \times 15. \]

Make sure to substitute the actual distances from the graph to get the numerical answers for each part of this question.

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