A tie bar is made of a material having a tensile strength of 231MPa and has to carry a load of 225kN. What is the diameter of the bar if a factor of safety of 7 is applied?

Question

Where do I begin?

Answer 1

Required capacity of bar (in tension)
=225kN*7
=1.575 MN
Tensile strength = 231 MPa
Area required
=1.575 MN / 231 MPa
=0.006818 m²
=6818 mm²

From πr²=6818
radius=√(6818/π)
= 46.6 mm (or more)