Asked by debra
a ticket booth sold 456 tickets and collected $2311.50 in ticket sales. Adult tickets are $6.50 and child tickets are $2. how many tickets of each type were sole?
Answers
Answered by
Person_blah
I'll try to help.
You know that a certain number of child tickets and a certain number of adult tickets must add up to equal 456.
Say x = adult tickets (number)
y = # child tickets
So x + y = 456
And the money collected is :
6.5x + 2y = 2311.5
2(x + y = 456) ==> 2x + 2y = 912.
6.5x + 2y = 2311.5
- (2x + 2y = 912)
4.5x = 1399.5
x = 1339.5 / 4.5 = 311
311 + y = 456
y = 145
SO # adult tickets = 311 # child tickets = 145
Hope that helped. Peace out.
You know that a certain number of child tickets and a certain number of adult tickets must add up to equal 456.
Say x = adult tickets (number)
y = # child tickets
So x + y = 456
And the money collected is :
6.5x + 2y = 2311.5
2(x + y = 456) ==> 2x + 2y = 912.
6.5x + 2y = 2311.5
- (2x + 2y = 912)
4.5x = 1399.5
x = 1339.5 / 4.5 = 311
311 + y = 456
y = 145
SO # adult tickets = 311 # child tickets = 145
Hope that helped. Peace out.
Answered by
Reiny
Adult tickets --->
children tickets --> 456-x
6.5x + 2(456-x) = 2311.5
times 2
13x + 4(456-x) = 4623
9x = 2799
x = 311
so 311 adult tickets and 145 children tickets
children tickets --> 456-x
6.5x + 2(456-x) = 2311.5
times 2
13x + 4(456-x) = 4623
9x = 2799
x = 311
so 311 adult tickets and 145 children tickets
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