Asked by sharkman

A thin non-uniform rod of length L=2.00 m and mass M=9.00 kg is free to pivot about an axis at one end. The CM of the rod is at a distance d=1.30 m from that end as illustrated below. The rod's moment of inertia about an axis through its CM and parallel to the rotation axis is ICM=2.57 kg m2.

The rod is released at rest from an angle θ=33.0°. Calculate the speed of the center of mass when the rod is horizontal.
Answered by tom
A thin uniform rod (length = 1.4 m, mass = 2.5 kg) is pivoted about a horizontal, frictionless pin through one end of the rod. (The moment of inertia of the rod about this axis is 1/3 ML2.) The rod is released when it makes an angle of 45° with the horizontal. What is the angular acceleration of the rod at the instant it is released?
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