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a thin metal ring of diameter is 0.6m and mass 1 kg starts rest and rolls down inclined plan.Its linear velocity is 5m/s .Calculate the moment of inertia and kinetic energy of rotation.

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omega is angular velocity in radians/second

omega R = 5 m/s
so
omega = 5/.3 = 16.7 radians/second

Ke = (1/2)I omega^2

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