The heat gained by the ice cubes in melting and rising ti the final temperature equals the energy lost by the coffee.
Write that as an equation and solve for the final temperature, T.
150*(85 - T) = 20*[80 + 1.0*(T - 0)]
12,750 - 150 T = 1600 + 20T
170 T = 11,150
T = ___ deg C
The 80 is the heat of fusion, in cal/g, and the 1.0 is the specific heat of water, in cal/(g*C)
A thermos contains 150cm3 of coffee at 85° C. To cool the coffee, you drop two 10g ice cubes into the thermos. The ice cubes are initially at 0° C and melt completely. What is the final temperature of the coffee? Treat the coffee as if it were water. (See Table 12.2 and Table 12.3 for appropriate constants.)
Please HELP!!!!
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