To find the number of seats in row 15, we can observe the pattern in the number of seats per row:
- Row 1: 41 seats
- Row 2: 44 seats
- Row 3: 47 seats
From this, we can see that each subsequent row increases by 3 seats. This indicates that the number of seats in each row forms an arithmetic sequence where:
- First term (Row 1): \( a_1 = 41 \)
- Common difference: \( d = 3 \)
The formula for the \( n \)-th term of an arithmetic sequence is given by:
\[ a_n = a_1 + (n-1) \cdot d \]
Where:
- \( a_n \) is the number of seats in row \( n \)
- \( a_1 \) is the number of seats in the first row
- \( d \) is the common difference
- \( n \) is the row number
Plugging in the values for row 15:
\[ a_{15} = 41 + (15-1) \cdot 3 \]
Calculating it:
\[ a_{15} = 41 + 14 \cdot 3 \] \[ a_{15} = 41 + 42 \] \[ a_{15} = 83 \]
So, there are 83 seats in row 15.