a. The value of \displaystyle \int_{-2}^{-1} \frac{14}{ 4 x } dx is

Question

b. The value of \displaystyle \int_{1}^{2} \frac{14}{ 4 x } dx is

Answer 1

a. \displaystyle \int_{-2}^{-1} \frac{14}{ 4 x } dx = \frac{7}{2} \ln|-2| - \frac{7}{2} \ln|-1| = \frac{7}{2} \ln(2) - \frac{7}{2} \ln(1) = \frac{7}{2} \ln(2)

b. \displaystyle \int_{1}^{2} \frac{14}{ 4 x } dx = \frac{7}{2} \ln|2| - \frac{7}{2} \ln|1| = \frac{7}{2} \ln(2) - \frac{7}{2} \ln(1) = \frac{7}{2} \ln(2)