(a) The solubility of bismuth iodide in water is 9.091 x 10-3 M. Calculate the value of the solubility product. The dissolution products are and

Answer 1

solubility = (x)*((x*3))^3

x=9.091*10-3

solubility = 1.84*10^-7

Answer 2

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Answer 3

5.043*10^-7