A tennis player throws a tennis ball vertically up with an initial velocity of 50m/s. Another player catches the ball after 0.43s. Find the time upward, time downward, and the vertical distance upward.

Answer 1

well, time up is the same as time down, the max height can be found at time .43/2.

hf=hi+vi*t-4.8t^2

Answer 2

It would have taken 50/9.8 or 5.1 seconds to get to the top of the arc. But person two caught it after .43 sec so it was on the way up. No downward. And y = 50*.43 - 4.9(.43^2) = 20.6m