A tennis player strikes a ball when it is 1 m above the ground, with a velocity 17 m/s at 30 degrees above the horizontal. The net is 4 m away horizontally and it is 0.6 m high. How high, vertically, above the net does the ball pass?
2 answers
It's my first time taking physics, how would I get to the answer?
how long does it take to get to the net? distance/horiz velocity
or timetoNet=4/17cos30
Now, the height at that time:
hf=hi+vvertical*t-4.9t^2 where vvertical is 17sin30
you know time t, and hi, solve for hf. How high above net? subtract .6 from hf.
or timetoNet=4/17cos30
Now, the height at that time:
hf=hi+vvertical*t-4.9t^2 where vvertical is 17sin30
you know time t, and hi, solve for hf. How high above net? subtract .6 from hf.
1 answer