A tennis player hits a 0.1-

Question

kilogram tennis ball with her
racket from the north end of a
court. Her racket was traveling
at 65 kilometers per hour. The
ball accelerated at a rate of
10 meters per second
squared. The ball hits the floor
on the south end of the tennis
court. The floor sends the ball
toward the tennis player's
opponent with the same
acceleration. How much force
did the floor on the south end
of the court exert on the ball?
6.5 N
7.5 N
0.01 N
1 N

Answer 1

To determine the force exerted by the floor on the ball, we can use Newton's second law of motion, which states:

\[ F = m \cdot a \]

where \( F \) is the force, \( m \) is the mass of the object, and \( a \) is the acceleration.

Given:

• Mass of the tennis ball (\( m \)) = 0.1 kg
• Acceleration (\( a \)) = 10 m/s²

Now we can calculate the force exerted on the ball by the floor:

\[ F = m \cdot a = 0.1 , \text{kg} \cdot 10 , \text{m/s}^2 = 1 , \text{N} \]

Thus, the force that the floor on the south end of the court exerted on the ball is 1 N.