A tennis player hits a 0.1-kilogram tennis ball with her racket from the north end of a court. Her racket was traveling at 65 kilometers per hour. The ball accelerated at a rate of 10 meters per second squared. The ball hits the floor on the south end of the tennis court. The floor sends the ball toward the tennis player's opponent with the same acceleration. How much force did the floor on the south end of the court exert on the ball? (1 point)

Answer 1

To find the force exerted by the floor on the ball, we can use Newton's second law of motion, which states that force is equal to mass times acceleration.

First, let's convert the racket's speed from kilometers per hour to meters per second:
65 kilometers per hour = 18.0556 meters per second

Now, let's calculate the force exerted by the racket on the ball before it hits the floor:
Force = mass x acceleration
Force = 0.1 kg x 10 m/s^2
Force = 1 N

Since the floor sends the ball towards the opponent with the same acceleration, the force exerted by the floor on the ball will also be:
Force = 0.1 kg x 10 m/s^2
Force = 1 N

Therefore, the floor on the south end of the court exerted a force of 1 Newton on the ball.