Question

A tennis player hits a 0.1-kilogram tennis ball with her racket from the north end of a court. Her racket was traveling at 65 kilometers per hour. The ball accelerated at a rate of 10 meters per second squared. The ball hits the floor on the south end of the tennis court. The floor sends the ball toward the tennis player's opponent with the same acceleration. How much force did the floor on the south end of the court exert on the ball?

Answer 1

To solve this problem, we can use Newton's second law of motion, which states that force (F) is equal to mass (m) times acceleration (a): F = ma.

First, we need to convert the velocity of the racket from kilometers per hour to meters per second:

65 km/hour = 18.06 m/s

Next, we can use the formula for acceleration to find the time it takes for the ball to hit the floor:

a = (v_f - v_i) / t

where a is the acceleration, v_f is the final velocity (0 m/s), v_i is the initial velocity (18.06 m/s), and t is the time.

Rearranging the formula, we get:

t = (v_f - v_i) / a

t = (0 - 18.06) / (-10)

t = 1.806 seconds

Now we can use the formula for distance to find the distance the ball travels before hitting the floor:

d = v_i * t + 0.5 * a * t^2

d = 18.06 * 1.806 + 0.5 * (-10) * (1.806)^2

d = 16.39 meters

Finally, we can use the formula for force to find the force exerted by the floor on the ball:

F = ma

F = 0.1 * 10

F = 1 Newton

Therefore, the floor on the south end of the court exerted a force of 1 Newton on the ball.

Answer 2

The wind blows a lawn chair that weighs 4 kg into a fence with a force of 8 N. How much reaction force does the fence exert on the chair?

Answer 3

8 N

Answer 4

hope im not too late

1 newton

2 force = mass × acceleration

3 1.6 N

4 1 N

5 8 N

hope this helped :)