A tennis ball with a velocity of 24.4 m/s
is thrown perpendicularly at a wall. After
striking the wall, the ball rebounds in the
opposite direction with a speed of 16 m/s.
If the ball is in contact with the wall for
0.013 s, what is the average acceleration of
the ball while it is in contact with the wall?
Answer in units of m/s
2
3 answers
acceleration=changevelocty/time=(24.4+16)/.013 m/s^2
24.4+16? If it's the change of velocity, wouldn't it be 24.4-16?
a=-16-24.4/.013
a=-40.4/.013
a=3107.69
a=-40.4/.013
a=3107.69
0 answers