A tennis ball is struck such that it leaves the racket horizontally with a speed of 53 m/s. The ball clears the net and hits the ground a horizontal distance 29 m from where it was hit. How long was the ball in the air and how high was the ball above the ground when it is hit?

Answer 1

time= distance/velocity

Now, knowing time in air,how far does a ball fall in that time?

distance=1/2 g time^2