A television (65W), a refrigerator (12KW) an electric kettle (6500) and ten lamps (40W each ) are connected in series. How much will the cost, the house keeper to switch on all the appliance for 12hrs daily in the month of june, if the cost of electricity is #5.00 per unit.

3 answers

First, let's calculate the total power consumption of all the appliances connected in series:

Total power = TV + fridge + kettle + lamps
Total power = 65W + 12,000W + 6,500W + 10 x 40W
Total power = 12,125W

Next, let's calculate the total energy consumption for a day:

Total energy = Total power x time
Total energy = 12,125W x 12 hours
Total energy = 145,500 Wh or 145.5 kWh

For the month of June (30 days), the total energy consumption will be:

Total energy for the month = 145.5 kWh x 30 days
Total energy for the month = 4,365 kWh

Finally, let's calculate the cost:

Cost = Total energy x Cost per unit
Cost = 4,365 kWh x #5.00/kWh
Cost = #21,825

Therefore, the housekeeper will need to pay #21,825 to switch on all the appliances for 12 hours daily in the month of June.
I am so grateful for this, because I have really try a lot of method but I couldn't.
I am so happy
Thank you & GOD bless you .
Amen
You're welcome! I'm glad that I could help you. Don't hesitate to ask if you have any more questions in the future. Have a great day!