mL1 x M1 = mL2 x M2
1.75 mL x 9.00M = mL2 x 2.50
Solve for mL2. That is the TOTAL volume needed. Technically you can't find the actual volume to be ADDED but it will be close if you subtract 1.75 L from the total. To make the solution accurately, however, you add the 1.75 L to a volumetric flask of the volume found for mL2 and add water to the final volume.
A technician measures 1.75 L of a standard solution of hydrochloric acid, HCl(aq), with a concentration of 9.00 mol/L. Determine the amount of water that must be added to create a solution with a concentration of 2.50 mol/L.
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