Let's denote the student's age as X years.
According to the information given:
Teacher's age = 2X + 6
Principal's age = 3X + 10
Now, we want to find out how many years older the principal is compared to the teacher. To do this, we subtract the teacher's age from the principal's age:
Principal's age - Teacher's age = (3X + 10) - (2X + 6)
Simplifying this expression, we get:
= 3X + 10 - 2X - 6
= (3X - 2X) + (10 - 6)
= X + 4
So, the principal is X + 4 years older than the teacher.
The correct answer is:
B.) X+4
A teacher's age is 6 years greater than 2 times a student's age. A principal's age is 10 years greater than 3 times the student's age
If X represents the student's age in years, which expression represents how many years older the principal is than the teacher?
A.) 4X+1
B.) x+4
C.) 4X+5
D.) X+16
1 answer