To find Mr. Brown's salary after teaching for 3, 4, and 5 years using the function \( s = 1,500y + 40,000 \):
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For \( y = 3 \) (after 3 years): \[ s = 1,500(3) + 40,000 = 4,500 + 40,000 = 44,500 \] So the point is \( (3, 44,500) \).
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For \( y = 4 \) (after 4 years): \[ s = 1,500(4) + 40,000 = 6,000 + 40,000 = 46,000 \] So the point is \( (4, 46,000) \).
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For \( y = 5 \) (after 5 years): \[ s = 1,500(5) + 40,000 = 7,500 + 40,000 = 47,500 \] So the point is \( (5, 47,500) \).
Combining these results, the points that represent Mr. Brown's salary after teaching for 3, 4, and 5 years are:
- \( (3, 44,500) \)
- \( (4, 46,000) \)
- \( (5, 47,500) \)
Thus, the correct response is:
(3, 44,500), (4, 46,000), and (5, 47,500).