To find Mr. Brown's salary for teaching 3, 4, and 5 years using the function \( s = 1,500y + 40,000 \), we can substitute \( y \) with 3, 4, and 5 respectively.
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When \( y = 3 \): \[ s = 1,500(3) + 40,000 = 4,500 + 40,000 = 44,500 \] So, the point is \( (3, 44,500) \).
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When \( y = 4 \): \[ s = 1,500(4) + 40,000 = 6,000 + 40,000 = 46,000 \] So, the point is \( (4, 46,000) \).
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When \( y = 5 \): \[ s = 1,500(5) + 40,000 = 7,500 + 40,000 = 47,500 \] So, the point is \( (5, 47,500) \).
Therefore, the points representing Mr. Brown's salary for teaching 3, 4, and 5 years are \( (3, 44,500) \), \( (4, 46,000) \), and \( (5, 47,500) \).
The correct response is: (3, 44,500), (4, 46,000), and (5, 47,500).