there are 20C3 ways to pick the boys
and 10C3 ways to pick the girls.
So, 20C3 * 10C3 ways to choose
No permutations involved, just combinations.
A teacher has 20 boys and 10 girls in her class. In how many way can she select 6 of the children to be in a play if she must have 3 boys and 3 girls?
1 answer