A taut massless string connects two boxes. The boxes are placed on an incline plane at θ = 32.00. What is the acceleration of boxes as they move down the incline, given m2 = 1.0 kg, m1 = 7.2 kg, μ2 = 0.10 and μ1 = 0.20.

Question

A taut massless string connects two boxes.  The boxes are placed on an incline plane at θ = 32.00.  What is the acceleration of boxes as they move down the incline, given m2 = 1.0 kg, m1 = 7.2 kg, μ2 = 0.10 and μ1 = 0.20.

bobpursley · Answer

total forces of friction:
(.2*m1*g + .1*m2*g)cosTheta
work that out.
gravity down the plane:
force=sinTheta(m1*g+m2*g)

acceleration=netforce/totalmass
where net force =sinTheta(m1*g+m2*g)-.2*m1*g + .1*m2*g)cosTheta

calculate acceleration

Johnn · Answer

could you show how you got that equation for the total friction and gravity down the plane