The dart can hit the green square if it lands anywhere within the boundaries of the green square. The green square has side length 8, so its area is 8 x 8 = <<8*8=64>>64 square units.
The yellow square is entirely contained within the green square. Since its side length is 4, its area is 4 x 4 = <<4*4=16>>16 square units.
Therefore, the theoretical probability that a dart will hit the green square is 64 - 16 = <<64-16=48>>48 square units.
The probability is therefore 48/64 = 3/4 = <<48/64=3/4>>3/4. Answer: \boxed{\frac{3}{4}}.
A target is made of a yellow square inside of a green square. What is the theoretical probability that a dart will hit the green square if the side length of the yellow square is 4, and the side length of the green square is 8?
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