v = x^2h, so
h = 1000/x^2
a = 2x^2 + 4xh = 2x^2 + 4000/x
da/dx = 4x - 4000/x^2
= 4(x^3-1000)/x^2
so, da/dx = 0 when x=10
a = 2*100 + 4*10*1000/100 = 600
as usual, area is minimum when the shape is a cube.
A tank with a square base of side x has a capacity of 1000m^3. If the total area is pm^3, show that p=2x^2+4000/x. Hence find the least area of the flat sheet that may be used to build the tank.
Please show workings
#thanks
1 answer