A tank with a length 4m, width 2m and depth 3m is filled with a liquid of density

Question

800kgm-3.What is the force acting on the bottom of the tankdue to that liquid pressure

Answer 1

The force acting on the bottom of the tank due to the liquid pressure can be calculated using the formula:

F = P x A

Where:
F is the force
P is the pressure
A is the area

To find the pressure, we use the formula:

P = ρgh

Where:
ρ is the density of the liquid
g is the acceleration due to gravity (approximately 9.8 m/s^2)
h is the height of the liquid column

Given:
ρ = 800 kg/m^3
g = 9.8 m/s^2
h = 3 m

Substituting these values into the formula, we can find the pressure:

P = 800 kg/m^3 x 9.8 m/s^2 x 3 m
P = 23,520 Pa

To find the area of the bottom of the tank, we use the formula:

A = length x width

Given:
length = 4 m
width = 2 m

Substituting these values into the formula, we can find the area:

A = 4 m x 2 m
A = 8 m^2

Now, we can calculate the force:

F = 23,520 Pa x 8 m^2
F = 188,160 N

Therefore, the force acting on the bottom of the tank due to the liquid pressure is 188,160 Newtons.