A tank was 1/3 full of water. After 2950 ml of water were added, the tank was 3/4 full of water. Find the capacity of the tank in litres.

Question

And the answer is not3.54

Answer 1

Let's assume the capacity of the tank is x ml.
We are given that the tank was initially 1/3 full of water, so the amount of water in the tank was (1/3)*x ml.

After 2950 ml of water were added, the tank was 3/4 full of water. So, the amount of water in the tank after adding 2950 ml is (3/4)*x ml.

Since the tank was initially 1/3 full and then 2950 ml were added, the total amount of water in the tank is (1/3)*x + 2950 ml.

According to the given condition, this amount of water is equal to (3/4)*x.

So, we can set up the equation:
(1/3)*x + 2950 = (3/4)*x.

Multiplying both sides of the equation by 12 (common denominator), we get:
4x + 35400 = 9x.

Simplifying the equation, we find:
5x = 35400.

Dividing both sides of the equation by 5, we get:
x = 7080.

Therefore, the capacity of the tank is 7080 ml or 7.08 liters.