A tall pea plant results from a dominant tall allele, while the short phenotype results from two recessive alleles. What is the probability of the plants producing short offspring (pp) when a tall pea plant with one tall allele (Pp) is cross-pollinated with a short pea plant (pp)? Hint: Make a punnett square to help you!(1 point)

Question

Responses

75%
75%

100%
100%

25%
25%

50%
50%

Answer 1

To determine the probability of producing short offspring (pp) from crossing a tall pea plant with the genotype Pp (heterozygous) and a short pea plant with the genotype pp (homozygous recessive), we can use a Punnett square.

1. Write down the genotypes of the parents:

   • Tall Pea Plant (Pp): P, p
   • Short Pea Plant (pp): p, p

2. Set up the Punnett square:

          P        p
       ----------------
    p |    Pp     |   pp  |
       ----------------
    p |    Pp     |   pp  |
       ----------------

3. Fill in the Punnett square:

   • The offspring genotypes from the cross will be:
     • Pp (tall) from P and p
     • pp (short) from p and p
     • Pp (tall) from P and p
     • pp (short) from p and p

4. Count the genotypes:

   • Pp: 2 (tall)
   • pp: 2 (short)

5. Calculate the probabilities:

   • Total possibilities: 4
   • Probability of short (pp) offspring: 2/4 = 1/2 = 50%

Thus, the probability of the plants producing short offspring (pp) is 50%.