A tall, heterozygous pea plant (Tt) is crossed with another tall, heterozygous pea plant. Use a Punnett square to determine the probability that the offspring is a short, homozygous pea plant (tt).(1 point)

Question

Responses

75%
75%

0%
0%

50%
50%

25%

Answer 1

To determine the probability of getting a short, homozygous pea plant (tt) from a cross between two heterozygous tall pea plants (Tt), we can set up a Punnett square.

1. The possible alleles from each parent (both Tt) are:

   • Parent 1: T, t
   • Parent 2: T, t

2. Setting up the Punnett square:

        T       t
      ------------
T |   TT    |   Tt   |
      ------------
t |   Tt    |   tt   |

3. The genotypes of the offspring are:

   • TT (tall): 1
   • Tt (tall): 2
   • tt (short): 1

4. Now we can count the genotypes:

   • 1 TT
   • 2 Tt
   • 1 tt

5. The probability of getting a short, homozygous plant (tt) is:

   • 1 tt out of 4 total offspring = 1/4 = 25%.

So, the correct response is 25%.