A tall, heterozygous pea plant (Tt) is crossed with another tall, heterozygous pea plant. Use a Punnett square to determine the probability that the offspring is a short, homozygous pea plant (tt).(1 point)

Question

Responses

0%
0%

50%
50%

75%
75%

25%

Answer 1

To solve this problem using a Punnett square, we begin by identifying the possible alleles for the tall (T) and short (t) traits.

We have two parent plants that are both heterozygous (Tt). When we set up the Punnett square, we will list the alleles from each parent on the top and side of the square.

Parent Alleles:

• Parent 1: T, t
• Parent 2: T, t

Setting up the Punnett Square:

| | T | t | |------|------|------| | T| TT | Tt | | t| Tt | tt |

Offspring Genotypes:

• TT (homozygous tall)
• Tt (heterozygous tall)
• Tt (heterozygous tall)
• tt (homozygous short)

Counting the Results:

From the Punnett square:

• 1 TT (homozygous tall)
• 2 Tt (heterozygous tall)
• 1 tt (homozygous short)

Calculating Probability:

• Total offspring = 4
• Offspring that are tt = 1

So, the probability of having a short, homozygous plant (tt) is: \[ \frac{1}{4} \times 100 = 25% \]

Conclusion:

The probability that the offspring is a short, homozygous pea plant (tt) is 25%.