A tall, heterozygous pea plant is cross-pollinated with another tall, heterozygous pea plant. Use a Punnett square to determine the probability that the offspring is a tall, homozygous pea plant.(1 point)

Question

Responses

50%
50%

0%
0%

25%
25%

75%

Answer 1

To solve this problem, we can define the traits involved:

• "Tall" (T) is dominant.
• "Short" (t) is recessive.

Both parent plants are heterozygous tall, meaning their genotypes are Tt.

When we perform a Punnett square for the cross Tt x Tt, we get the following combinations:

          T        t
        ------------
    T |      TT      |     Tt     |
        ------------
    t |      Tt      |     tt     |

From the Punnett square, we can summarize the genotypes of the offspring:

• TT (homozygous tall): 1
• Tt (heterozygous tall): 2
• tt (homozygous short): 1

This gives us a total of 4 offspring genotypes:

• 1 TT
• 2 Tt
• 1 tt

Now we want the probability of having a tall, homozygous pea plant (TT). There is 1 TT out of 4 total genotypes.

Therefore, the probability of producing a tall, homozygous (TT) offspring is:

\[ \frac{1}{4} = 25% \]

The correct answer is 25%.