Question

A tall, heterozygous pea plant is cross-pollinated with another tall, heterozygous pea plant. Use a Punnett square to determine the probability that the offspring is a tall, homozygous pea plant.(1 point)
Responses

50%
50%

0%
0%

25%
25%

75%

Answer 1

To solve this problem, we can define the traits involved:

- "Tall" (T) is dominant.
- "Short" (t) is recessive.

Both parent plants are heterozygous tall, meaning their genotypes are Tt.

When we perform a Punnett square for the cross Tt x Tt, we get the following combinations:

```
T t
------------
T | TT | Tt |
------------
t | Tt | tt |
```

From the Punnett square, we can summarize the genotypes of the offspring:

- TT (homozygous tall): 1
- Tt (heterozygous tall): 2
- tt (homozygous short): 1

This gives us a total of 4 offspring genotypes:

- 1 TT
- 2 Tt
- 1 tt

Now we want the probability of having a tall, homozygous pea plant (TT). There is 1 TT out of 4 total genotypes.

Therefore, the probability of producing a tall, homozygous (TT) offspring is:

\[
\frac{1}{4} = 25\%
\]

The correct answer is **25%**.