A tall, heterozygous pea plant is cross-pollinated with another tall, heterozygous pea plant. Use a Punnett square to determine the probability that the offspring is a tall, homozygous pea plant.(1 point)

Question

Responses

0%
0%

25%
25%

75%
75%

50%

Answer 1

To solve this problem, we start with the genotypes of the parent plants. Both parent pea plants are tall and heterozygous, meaning their genotype is Tt, where 'T' represents the tall allele (dominant) and 't' represents the short allele (recessive).

We can use a Punnett square to determine the offspring's genotypes.

1. Set up the Punnett square:

        T         t
      ----------------
   T |    TT    |   Tt   |
      ----------------
   t |    Tt    |   tt   |
      ----------------

2. Now, let's analyze the possible genotypes of the offspring:

• TT: Homozygous tall (1 square)
• Tt: Heterozygous tall (2 squares)
• tt: Homozygous short (1 square)

3. Now, to find the probability of the offspring being a tall homozygous plant (TT), we note that there is 1 TT out of a total of 4 squares.

4. The probability is calculated as follows:

\[ \text{Probability(TT)} = \frac{\text{Number of TT squares}}{\text{Total number of squares}} = \frac{1}{4} = 25% \]

Therefore, the probability that the offspring is a tall, homozygous pea plant is 25%.