A tailback initially running at a velocity of 6.6 m/s becomes very tired and slows down at a uniform rate of 0.55 m/s2. How fast will he be running after going an additional 6.2 meters?

1 answer

Vf^2=Vi^2+2ad
a= -.55m/s^2, d=6.2, Vi=6.6, solve for Vf