To find the equation that models the linear relationship presented by the given table of values, we need to calculate the slope (m) and the y-intercept (b) of the line in slope-intercept form, which is expressed as \( y = mx + b \).
From the table:
\[ \begin{array}{c|c} x & y \ \hline -2 & -7 \ 0 & -3 \ 2 & 1 \ 4 & 5 \ \end{array} \]
We can calculate the slope \( m \) using any two points from the table. Let's take the points \( (0, -3) \) and \( (2, 1) \):
\[ m = \frac{y_2 - y_1}{x_2 - x_1} = \frac{1 - (-3)}{2 - 0} = \frac{4}{2} = 2 \]
Now, using the slope \( m = 2 \) and the point \( (0, -3) \) (where \( x = 0 \) gives us the y-intercept \( b \)), we can express the equation as:
\[ y = 2x + b \]
Since when \( x = 0 \), \( y = -3 \):
\[ -3 = 2(0) + b \implies b = -3 \]
Thus, the equation in slope-intercept form is:
\[ y = 2x - 3 \]
The correct response is:
y = 2x - 3