a.
√(128/2) = 8.
x=(-0.3/8)sin8t+0.05cos8t
x=-0.0375sin8t+0.05cos8t
b.
A=+√( (0.05)^2 + ((-0.3)^2/(8)^2) ) = 0.062
sinϕ= (0.05/0.062) =0.806
cosϕ= (-0.3/0.062 *8) =-0.605
ϕtan= tan^-1 (0.806/-0.605) = tan^-1 (-1.333)=-0.927
-0.0927+π=2.217 rad
x= 0.062sin ( 8t + 2.214)m
A system is represented by the equation:
2x”+128x = f(t)
Obtain the free response of the system in the form
a) x = A sin wn (t ) + B cos wn (t)
b) x= A sin wn (t) + ϕ
The initial conditions are x(0) = 0.05m and x’ = 0.3m/s.
2 answers
Note: The values for part (a) are incorrect, as they do not satisfy the given initial conditions. Here is the corrected solution:
a.
The characteristic equation of the system is:
2λ^2 + 128 = 0
Solving for λ, we get:
λ = ±8i
Since the roots are imaginary, the general solution for the homogeneous equation is:
xh = c1 cos(8t) + c2 sin(8t)
To find the particular solution, we assume a sinusoidal form of the input:
f(t) = F sin(ωt)
Substituting into the equation of motion, we get:
-ω^2 F sin(ωt) + 128x = F sin(ωt)
x = (1/128-ω^2) F sin(ωt)
Comparing this to the form x = A sin(ωt) + B cos(ωt), we can see that:
A = 0
B = F/(128-ω^2)
ω = 8 (since we want the frequency of the output to be the same as the natural frequency of the system)
Therefore, the particular solution is:
xp = (1/1201) F sin(8t)
The total solution is the sum of the homogeneous and particular solutions:
x = xh + xp
x = c1 cos(8t) + c2 sin(8t) + (1/1201) F sin(8t)
Using the initial conditions x(0) = 0.05 and x' = 0.3, we get the following system of equations:
c1 + (1/1201) F = 0.05
8c2 = 0.3
Solving for c1 and c2, we get:
c1 = -0.0373
c2 = 0.0375
Therefore, the free response of the system is:
x = -0.0373 cos(8t) + 0.0375 sin(8t) + (1/1201) F sin(8t)
b.
Using the same particular solution as in part (a):
xp = (1/1201) F sin(8t)
We can write the total solution as:
x = A sin(8t + ϕ) + (1/1201) F sin(8t)
Using the initial conditions x(0) = 0.05 and x' = 0.3, we get the following system of equations:
A sin ϕ = 0.05
A ω cos ϕ + (1/1201) F = 0.3
Substituting ω = 8 and solving for A and ϕ, we get:
A = 0.062
ϕ = -0.925 (in radians) or -53.13°
Therefore, the free response of the system is:
x = 0.062 sin(8t - 0.925) + (1/1201) F sin(8t)
a.
The characteristic equation of the system is:
2λ^2 + 128 = 0
Solving for λ, we get:
λ = ±8i
Since the roots are imaginary, the general solution for the homogeneous equation is:
xh = c1 cos(8t) + c2 sin(8t)
To find the particular solution, we assume a sinusoidal form of the input:
f(t) = F sin(ωt)
Substituting into the equation of motion, we get:
-ω^2 F sin(ωt) + 128x = F sin(ωt)
x = (1/128-ω^2) F sin(ωt)
Comparing this to the form x = A sin(ωt) + B cos(ωt), we can see that:
A = 0
B = F/(128-ω^2)
ω = 8 (since we want the frequency of the output to be the same as the natural frequency of the system)
Therefore, the particular solution is:
xp = (1/1201) F sin(8t)
The total solution is the sum of the homogeneous and particular solutions:
x = xh + xp
x = c1 cos(8t) + c2 sin(8t) + (1/1201) F sin(8t)
Using the initial conditions x(0) = 0.05 and x' = 0.3, we get the following system of equations:
c1 + (1/1201) F = 0.05
8c2 = 0.3
Solving for c1 and c2, we get:
c1 = -0.0373
c2 = 0.0375
Therefore, the free response of the system is:
x = -0.0373 cos(8t) + 0.0375 sin(8t) + (1/1201) F sin(8t)
b.
Using the same particular solution as in part (a):
xp = (1/1201) F sin(8t)
We can write the total solution as:
x = A sin(8t + ϕ) + (1/1201) F sin(8t)
Using the initial conditions x(0) = 0.05 and x' = 0.3, we get the following system of equations:
A sin ϕ = 0.05
A ω cos ϕ + (1/1201) F = 0.3
Substituting ω = 8 and solving for A and ϕ, we get:
A = 0.062
ϕ = -0.925 (in radians) or -53.13°
Therefore, the free response of the system is:
x = 0.062 sin(8t - 0.925) + (1/1201) F sin(8t)