A swimming pool has a base 10 m by 12 m. Water evaporates from the pool at a constant rate of 10 liters per hour. Find the amount of water lost in one week and the change of depth in one week.

Answer 1

1 week = 7 days

1 week = 7 days ∙ 24 h = 168 h

1 m³ = 1000 ℓ

1 ℓ = 1 / 1000 m³ = 0.001 m³

10 ℓ = 10 / 1000 m³ = 0.01 m³

168 ∙ 10 ℓ = 1680 ℓ

The amount of water lost in one week = 1680 ℓ

1680 ℓ = 1680 / 1000 =1.68 m³

V = volume of water lost = 1.68 m³

d = the change of depth

V = 10 m ∙ 12 m ∙ d = 1.68 m³

120 ∙ d = 1.68 Divide both sides by 120

d = 1.68 / 120

d = 0.014 m = 14 mm

By the way 1 mm = 1 m / 1000 = 0.001 m