Tan A = Y/X = 4/2 = 2.00.
A = 63.43o N. of E. = 26.57o E. of N.
Direction = 26.57o W. of N.
d = V*t = 0.6 km.
4*t = 0.6
t = 0.15 h. = 9 Min.
A swimmer wishes to swim across a river 600m wide. If he can swim at the rate of 4 km/h in still water and the river flows at 2 km/h, then in what direction must he swim to reach a point exactly opposite to the starting point and when will he reach it?
I have no idea how to solve this one.
2 answers
sin A=(2/4)=30 degree
time =s/v
600/root4^2-2^2
173.2seconds
time =s/v
600/root4^2-2^2
173.2seconds
2 answers