A swimmer is heading straight for the other shore of a river with a velocity of vs=0.7 m/s relative to the water, but is carried away by the current, which has a velocity of vr=0.3 m/s. It takes her 20.3 s to get across. How far downstream does she end up?

Question

A swimmer is heading straight for the other shore of a river with a velocity of vs=0.7 m/s relative to the water, but is carried away by the current, which has a velocity of vr=0.3 m/s. It takes her 20.3 s to get across. How far downstream does she end up? 
This is what I did but it is wrong. Can someone help me?
20.3/0.6=29

bobpursley · Answer

distance=velocityriver*time This is vastly different from what you did, and I don't understand what you did.

Hunde · Answer

Vs=0.7 relative to water,Vr=0.3&t=20.3sec then,Vsr=Vm-Vr,0.7+0.3=1m/s. V=s/t ,s=vt ,20.3m