say the water is moving in x direction at 4 km/h
say we swim in y direction at 3 km/h
then our speed is sqrt (3^2+4^2) = 5 km/h
tan angle above x axis is
tan theta = 3/4 = .75
A swimmer can swim in stillwater at a rate 4 kilometre per hour. If he swims in a river flowing at 3 kilometre per hour and keeps his direction with respect to water perpendicular to the current,find his velocity city with respect to the ground
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