A survey of 90 families showed that 40 owned at least one gun. Find the 95%

Question

confidence interval of the true proportion of families who own at least one gun.
Example

Answer 1

Example of a proportional confidence interval formula:

CI95 = p + or - (1.96)[√(pq/n)]
...where p = x/n, q = 1 - p, and n = sample size.
Note: + or - 1.96 represents 95% confidence interval.

For p in your problem: 40/90 = 0.44
For q: 1 - p = 1 - 0.44 = 0.56
n = 90

I let you take it from here to calculate the interval.

Answer 2

89.98 to 90.02