The probability of selecting an employee who eats breakfast or lunch at the office is the total number of employees who eat breakfast or lunch divided by the total number of employees surveyed.
There are 20 employees who eat breakfast, 50 employees who eat lunch, and 15 employees who eat both breakfast and lunch. So the total number of employees who eat breakfast or lunch is 20 + 50 - 15 = 55.
So the probability of selecting an employee who eats breakfast or lunch is 55 out of 80, which simplifies to 11 out of 16.
A survey of 80 employees was conducted asking about which meals they
regularly eat at the office. Twenty employees eat breakfast at the office, 50
eat lunch, and 15 eat both breakfast and lunch. If an employee is randomly
selected from this group, what is the probability of randomly selecting an
employee who eat breakfast or lunch at the office? Explain how you got the
answer.
write a simple answer by a 6th grader
1 answer