A SUPERSONIC FIGHTER JET FLYING HORIZONTALLW AT HEIGHT OF 4KM ABOVE THE GROUND AND AT A SPEED OF 400M/S FIRES A ROCKET VERTICALLY DOWNWARD. THE ROCKET IS RELEASED WITH AN INITIAL SPEED OF 80M/S CALCULATE THE TIME OF FLIGHT OF THE ROCKET AND THE HORIZONTAL DISTANCE FROM THE POINT OF ITS RELEASE AT WHICH THE ROCKET LANDS

Answer 1

No need to shout.
4000 = 80t + 4.9 t^2
You'll have to solve the quadratic
Horizontal will be 400t