A sum of N18100 was shared among 5 boys and 4 girls with each boy taking N20 more than each girl. find the boy's share.

1 answer

Let the share of each girl be \( x \). According to the problem, each boy receives \( x + 20 \).

Since there are 5 boys and 4 girls, we can express the total amount shared among them as follows:

\[ \text{Total amount} = \text{Amount received by boys} + \text{Amount received by girls} \]

The amount received by the boys can be represented as:

\[ 5(x + 20) \]

And the amount received by the girls is:

\[ 4x \]

Putting it all together, the total amount shared can be written as:

\[ 5(x + 20) + 4x = 18100 \]

Now, let's simplify the equation:

\[ 5x + 100 + 4x = 18100 \]

Combining like terms gives us:

\[ 9x + 100 = 18100 \]

Next, subtract 100 from both sides:

\[ 9x = 18100 - 100 \]

\[ 9x = 18000 \]

Now, divide by 9 to find \( x \):

\[ x = \frac{18000}{9} = 2000 \]

So, the share of each girl is \( N2000 \). Consequently, the share of each boy, which is \( x + 20 \), is:

\[ \text{Boy's share} = 2000 + 20 = 2020 \]

Thus, the boy's share is:

\[ \boxed{2020} \]