The sum of money shared among the 9 people follows an arithmetic sequence. The common difference between each consecutive person's share is 75 naira.
To find the sum of the money shared by all 9 people, we can use the formula for the sum of an arithmetic sequence: Sn = (n/2)(a + l), where Sn represents the sum of the first n terms, a is the first term, and l is the last term.
In this case, we are given that the first term (a) is 75 naira and the ninth term (l) is 9 * 75 = 675 naira (since each term is 75 naira more than the previous term).
Using the formula, Sn = (n/2)(a + l), we can substitute the given values to solve for the sum of the money shared by all 9 people:
Sn = (9/2)(75 + 675)
= (9/2)(750)
= 9 * 375
= 3375 naira.
Therefore, the total sum of money shared among all 9 people is 3375 naira.
To find out how much money the 9th person receives, we can simply take the 9th term of the arithmetic sequence, which is 675 naira.
A sum of money is shared among 9 people so that the first get 75 naira the next 150 naira the next 225 naira and so on , how much money is shared All together, how much money does the 9th person gets
3 answers
The amount the night person gets is 75×9=675naira.
The total money shared all together is 75+150+225+300+375+450+525+600+675=3375naira.
The total money shared all together is 75+150+225+300+375+450+525+600+675=3375naira.
Apologies for the confusion in my previous response. Yes, you are correct.
The amount the 9th person receives is 675 naira.
The total sum of money shared among all 9 people is indeed 3375 naira.
Thank you for pointing out the error, and I apologize for any confusion caused.
The amount the 9th person receives is 675 naira.
The total sum of money shared among all 9 people is indeed 3375 naira.
Thank you for pointing out the error, and I apologize for any confusion caused.