A sum of money is divided among three persons, X,Y and z in the ratio of 10:7:5. if Y gets $14 more then Z, how much X will get and what is the total sum of money?

Answer 1

x/y = 10/7
y/z = 7/5
y = z+14

Answer 2

>10 + 7 + 5 = 22
thus there are 22 shares.
let A be the total money.
> X = (10/22)A
> Y = (7/22)A
> Z = (5/22)A
Given That:
> Y = Z + 14
> (7/22)A = (5/22)A + 14
> (7/22)A - (5/22)A = 14
> (2/22)A = 14
> A = (22/2)14
> A = 154
total amount is $154.00
> X = (10/22)A
> X = (10/22)(154)
> X = 70
X gets $70.00

Answer 3

154

Answer 4

if a/b 1/3 b/c 2/5 then find a/c

Answer 5

To find the value of a/c, we need to find a common ratio between a, b, and c.

Since a/b = 1/3 and b/c = 2/5, we can multiply these ratios to find a common ratio:

(a/b) * (b/c) = (1/3) * (2/5)
a/bc = 2/15

Now we can isolate a/c by multiplying both sides of the equation by c:

(a/bc) * c = (2/15) * c
a = (2c)/15

Therefore, the value of a/c is (2c)/15.