To determine the increase in temperature (\( \Delta T \)) of the substance, we can use the formula for heat transfer:
\[ q = m \cdot c \cdot \Delta T \]
where:
- \( q \) is the heat added (in joules),
- \( m \) is the mass of the substance (in grams),
- \( c \) is the specific heat capacity (in J/g°C),
- \( \Delta T \) is the change in temperature (in °C).
From the problem, we have:
- \( q = 2000.0 , \text{J} \)
- \( m = 10.0 , \text{g} \)
- \( c = 0.870 , \text{J/g°C} \)
We can rearrange the equation to solve for \( \Delta T \):
\[ \Delta T = \frac{q}{m \cdot c} \]
Now, substituting in the values:
\[ \Delta T = \frac{2000.0 , \text{J}}{10.0 , \text{g} \cdot 0.870 , \text{J/g°C}} \]
Calculating the denominator:
\[ 10.0 , \text{g} \cdot 0.870 , \text{J/g°C} = 8.7 , \text{J/°C} \]
Now substituting back into the equation:
\[ \Delta T = \frac{2000.0 , \text{J}}{8.7 , \text{J/°C}} \approx 229.89 , \text{°C} \]
Rounding to one decimal place, we have:
\[ \Delta T \approx 230.0 , \text{°C} \]
Thus, the increase in temperature is approximately \( 230°C \).
The correct answer is 230°C.